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How to take object out of array based on attribute value with TypeScript?

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Sometimes, we want to take object out of array based on attribute value with TypeScript.

In this article, we’ll look at how to take object out of array based on attribute value with TypeScript.

How to take object out of array based on attribute value with TypeScript?

To take object out of array based on attribute value with TypeScript, we can use the array find method.

For instance, we write

const array = [
  { id: 1, value: "itemname" },
  { id: 2, value: "itemname" },
];

const item1 = array.find((i) => i.id === 1);

to get the item with id 1 from array and return it with

array.find((i) => i.id === 1)

We call find with a callback that returns the condition of the item we’re looking for in array.

Conclusion

To take object out of array based on attribute value with TypeScript, we can use the array find method.

By John Au-Yeung

Web developer specializing in React, Vue, and front end development.

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